{4/y+1=3/x+2 2x=1+3y

4/y+1=3/x+2 (可见x，y不等于0，等式两边同乘以xy)
4x+xy=3y+2xy
4x=3y+xy

又2x=1+3y ==〉x=（1+3y ）/2
带入上式：4*[（1+3y ）/2]=3y+[（1+3y ）/2]*y
3y^2-5y-4=0
(y-5/6)^2=73/36
解得：y1=5/6+√73/6=(5+√73)/6,y2=(5-√73)/6
y1^2=(49+5√73)/18,y2^2=(49-5√73)/18

(-5+y)(-5-y)=(-5)^2-y1^2=25-y1^2=(401-5√73)/18
(-5+y)(-5-y)=(-5)^2-y2^2=25-y2^2=(401+5√73)/18

你写清楚点，我现在算是：3y(2)-5y-4=0,后便会算了吧!
y(2)是平方．